2/3x+2=(1/3)-^1

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Solution for 2/3x+2=(1/3)-^1 equation: 



2/3x+2=(1/3)-^1

We move all terms to the left:

2/3x+2-((1/3)-^1)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

2/3x+2-((+1/3)-^1)=0

We calculate fractions


()/9x^2+(-((+1*3x)/9x^2+2=0

We calculate fractions

We do not support expression: x^4

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